For the differential equation `(x^2y^2)dx2xy dy=0`, which of the following are true (A) solution is `x^2y^2=cx` (B) `x^2y^2=cx` `x^2y^2=xc` (D) `yCalculus Find dy/dx y=3x^2 y = 3x2 y = 3 x 2 Differentiate both sides of the equation d dx (y) = d dx (3x2) d d x ( y) = d d x ( 3 x 2) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate the right side of the equation Tap for more stepsSimplify 1 5√6 √24 A 3√6 2 Evaluate 3y 5xy x for x = 4 and y = 2 A 42 3 Simplify 3x (5y 4) 2xy 10x 6x^2 A 3xy 2x 6x^2 4 Evaluate 5^3 A 1/125 5 Simplify ( (2x^4y^7)/ (x^5))^3 Assume all variables are nonzero A
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Y 2x 2 3x 2 then dy/dx
Y 2x 2 3x 2 then dy/dx-Click here👆to get an answer to your question ️ Solve (x^3 3xy^2) dx (y^3 3x^2y)dy = 0Solve The Differential Equation We are given a firstorder differential equation of the form {eq}P \ dx Q \ dy = 0 {/eq} Integration and differentiation are related to each other




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Simple and best practice solution for (x4y^3)dx2(x^2y)dy=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve it Explanation dy dx = 2x (y x2y)2 this is separable dy dx = 1 y2 ⋅ 2x (1 x2)2 y2 dy dx = 2x (1 x2)2 ⇒ y3 3 = − 1 1 x2 CFrom question, the equation given is (2x) 2y = 4e (2x2y) On applying log e both sides, log e (2x) 2y = log e 4 log e e (2x2y) ∵ log e n m = m log e n and log e e x = f(x) ⇒ 2y log e (2x) = log e 2 2 (2x – 2y) ⇒ (2 log e (2x) 2)y = 2x 2 log e (2) \(\therefore y = \frac{{x lo{g_e}2}}{{1 lo{g_e}\left( {2x} \right)}}\)
Given y = 2x^2 3x 2 find dy/dx To get dy/dx from a formula y in terms of x we must differentiate y with respect to x Generic formula for term differentiation d/dx (ax^b) = bax^b1 = times the coefficient by the power and minus the power by one Applying to each term in the formula gives us dy/dx = 4x 3 Answered by Alex O • Maths tutorX2y3 (xxy2) dy dx = 0 is not separable, since (x 2y3) y = 3x 2y2, but (x xy ) x = 1 y However, after multiplication by µ(x,y) = 1/(xy3), we get x2y3 xy 3 x(1y2) xy dy dx = 0 Simplify x(y −3 y 1) dy dx = 0 Note that this becomes separable, so it is also exact Using the methods from this section, f(x,y) = Z M dx = 1 2 x2 g(yEvaluate the following d/dy(x) at y = 2 x^6 (8 x^3 x^2)/2 Simplify the given value y = 2 x^6 (8 x^3 x^2)/2 y = 2 x^6 4 x^5 Take the derivative of x with respect to y d/dy(x) = 0 Substitute 2 x^6 4 x^5 for y in the derivative Answer 0_
If dy/dx = y/x and y(2) = 6, then y = 3x y = 1/2x^2 x 4 y = x 4 y = 3 squareroot 8x^2 y = 2x 2 Get more help from Chegg Solve it with our calculus problem solver and calculator(2,5) This problem has been solved!Here we look at doing the same thing but using the "dy/dx" notation (also called Leibniz's notation) instead of limits We start by calling the function "y" y = f(x) 1 Add Δx When x increases by Δx, then y increases by Δy y Δy = f(x Δx) 2 Subtract the Two Formulas




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A dy/dx = 3x 2 10 B dy/dx = 3x 2 5 C dy/dx = 3x 2 9 D dy/dx = 2x 2 – 8 6 If s(t) is a position of the moving object at time t The derivative of a function t s (t) A The velocity B The acceleration C The direction of the motion D The speed 7Measuring change in a linear function y = a bx a = intercept b = constant slope ie the impact of a unit change in x on the level of y b = = x y ∆ ∆ 2 1 2If y = 2x 2 3x then dy/dx is 4x 4x 3 3x Answer2 If D is the number of units demanded and the price is p = 30 D , then the revenue when D =2 is Rs—–




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Chain Rule of Differentiation in Calculus The chain rule of differentiation of functions in calculus is presented along with several examples and detailed solutions and comments Also in this site, Step by Step Calculator to Find Derivatives Using Chain RuleThe equation is also not separable The equation is also not homogenous, I don't think So what do I do?$$(y^2xy)dxx^2dy=0$$ Need step by step answer Thank you in advance for your help



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Calculusstudyguide
Solve the differential equation dy/dx = 6x^2 4x 9 dy/dx = 6x 2 4x 9 dy = (6x 2 4x 9) dx integrating gives y= (6x 3 /3) (4x 2 /2) 9x c y= 2x 3 2x 2 9x c If given boundary conditions of y (0)=0 then 0 = 2 (0) 3 2 (0) 2 9 (0) c therefore c=0 THeorem Double Integrals over Nonrectangular Regions Suppose g(x, y) is the extension to the rectangle R of the function f(x, y) defined on the regions D and R as shown in Figure 1421 inside R Then g(x, y) is integrable and we define the double integral of f(x, y) over D by ∬ D f(x, y)dA = ∬ R g(x, y)dAIn this case, we have (2x 2y) (1 dy/dx) The method is to split one of the binomials into its two terms and then multiply each term methodically by the two terms of the second binomial So, as he says, multiply (2x 2y) times 1 and (2x 2y) times 1 (dy/dx) to get (2x 2y) (2y 2x)dy/dx = 1 dy/dx



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The derivative of y with respect to t of `y=2x^25x` at x=3 with `(dx)/(dt)=2` is 14 This result can be interpreted as follows let p be a point on the parabola given by `y=2x^25x`Simple and best practice solution for (2xyy^2)dx2x^2dy=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homeworkGiven differential equation is y"=1 (y')^2,where y'=dy/dx and y"=d^2y/dx^2 Put y'=p so that p'=1p^2 =>dp/ (1p^2)=dx Variables are separableIntegrating both the sides we get tan^1 (p)=xA Given differential equation is y"=1 (y')^2,where y'=dy/dx and y"=d^2y/dx^2




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