For the differential equation `(x^2y^2)dx2xy dy=0`, which of the following are true (A) solution is `x^2y^2=cx` (B) `x^2y^2=cx` `x^2y^2=xc` (D) `yCalculus Find dy/dx y=3x^2 y = 3x2 y = 3 x 2 Differentiate both sides of the equation d dx (y) = d dx (3x2) d d x ( y) = d d x ( 3 x 2) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate the right side of the equation Tap for more stepsSimplify 1 5√6 √24 A 3√6 2 Evaluate 3y 5xy x for x = 4 and y = 2 A 42 3 Simplify 3x (5y 4) 2xy 10x 6x^2 A 3xy 2x 6x^2 4 Evaluate 5^3 A 1/125 5 Simplify ( (2x^4y^7)/ (x^5))^3 Assume all variables are nonzero A
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